Question

Sodium hydroxide reacts with ascorbic acid to produce sodium ascorbate and water. Below is the chemical equation: 2NaOH(aq) + H2C6H60(aq) → Na2C6H606(aq) + 2H20(1) Part A - Standardization of the NaOH Solution Trial 1 Trial 2 Trial 3 --------------- 0.4 g Mass of Ascorbic Acid (g) Moles Ascorbic Acid Moles NaOH based on stoichiometry ----------- NaOH Initial Volume (V;) 0.00 mL -------- -----------m L NaOH final Volume (V) 22.5 mL --------mL ----mL ---ml -----mL ------------mL NaOH Volume Used Vi-V; NaOH Molarity ---------------M

Answer 1

The moles of ascorbic acid are calculated:

n Acid = g / MM = 0.4 g / 176.12 g / mol = 0.0023 mol

The moles of NaOH are calculated:

n NaOH = 0.0023 mol AA * (2 mol NaOH / 1 mol AA) = 0.0046 mol

The final volume of NaOH is 22.5 mL (0.0225 L)

The molarity is calculated:

M = n / V = ​​0.0046 / 0.0225 = 0.2 M

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