Question

29. What is the mass if ammonia (NH3) neces oxygen? nia (NH) recessary to produce 0.340 mol NO in the presence of excess A) 1.45g 4NH, (g) + 502 (g) → 4NO(g) + 6H20(1) B) 4.359 C) 5.219 D) 5.799 E) 10.29

Answer 1

(29) Given enuation 2NH (9)+52 (9) 4 No (9) +674 060) From the balanced equation 4 moles of Nih produce 4 moles of No. 1 mole Nty = 179/mol. 1 mole No = 309/mo But Given o. 34 mol of No 4 mole Nth - 4 mole no - mole NH3 0.34 mole No 4 mole NHL 2 X 0.34 mole No = 0.34 mole NHL 4 mole No 1 mole Ni = 179, then o. 34 mole Nh an lig X 0.34 mole = 5.789 1 mole . Answeg D = 5.79g of Nithy required.