Homework Answers
Solution:
electric flux is the anount of electric field passing through a particular area hence option A is correct
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oy direction 13. The electric flux through a surface: A) is the amount of electric field...
Physics 222 Name: Task 7: Electric Flux and Gauss's Law Objective: To illustrate the concept of...
Physics 222 Name: Task 7: Electric Flux and Gauss's Law Objective: To illustrate the concept of "flux" and to avoid performing the integral in Gauss's Law for Electricity 1. A cylindrical Gaussian surface (length = 0.80 m, diameter = 0.20 m) is drawn in an area of a non-uniform electric field, directed at all points in the ex direction (i.e. horizontal to the right). The field varies with x, but does not vary with respect to y or z. The...
To calculate the electric flux through a surface of arbitrary shape you need to: a. multiply...
To calculate the electric flux through a surface of arbitrary shape you need to: a. multiply the total area of the surface by the average magnitude of the electric field at the surface. b. split the surface into small areas, and then add up the product of the perpendicular component of the electric field through each small area times the small area. c. split the surface into small areas, and then add up the product of the electric field times...
8) A negative charge, if free, tries to move A) in the direction of the electric...
8) A negative charge, if free, tries to move A) in the direction of the electric field. B) from low potential to high potential. C) from high potential to low potential. D) away from infinity. E) toward infinity. 9) Gaussian surfaces A and B enclose the same positive charge +Q. The area of Gaussian surface A is three times larger than that of Gaussian surface B. The flux of electric field through Gaussian surface A is A) nine times larger...
18a) Find the flux through the whole surface of the sphere. b) Find the magnitude and...
18a) Find the flux through the whole surface of the sphere. b) Find the magnitude and direction of E at the surface.1 Now put the same charge at the center of a spherical shell- with twice the diameter. c) Find the magnityde and direction of E at the surface.1 d) Find the flux through the whole surface of the sphere.1 e) Why is the flux the same, even though E is weaker?1 18, A particle with charge of 12.0 μC...
Please help !!! Calculate the magnitude of the flux of a constant electric field of 5.0...
Please help !!!
Calculate the magnitude of the flux of a constant electric field of 5.0 NC in the z -direction through a rectangle with area 4.0 m2 in the xy plane. a. 0 b. 5.0 N-m2/C c. 10.0 N-m2/C d. 20.0 N-m/C 10. 11. A circular ring of charge of radius b has a total charge q uniformly distributed around it. The electric field at the center of the ring is a. 0 12. A solid spherical conductor has...
A flat surface of area 3.10 m2 is rotated in a uniform electric field of magnitude...
A flat surface of area 3.10 m2 is rotated in a
uniform electric field of magnitude E = 5.20 105 N/C.
(a) Determine the electric flux through this area when the
electric field is perpendicular to the surface.
N · m2/C
(b) Determine the electric flux through this area when the electric
field is parallel to the surface.
N · m2/C
Part A If the electric flux through a closed surface is zero, the electric field at...
Part A If the electric flux through a closed surface is zero, the electric field at points on that surface must be zero. True False Submit Request Answer
Physics 222 Name: Task 7: Electric Flux and Gauss's Law Objective: To illustrate the concept of "flux" and to avoid performing the integral in Gauss's Law for Electricity 1. A cylindrical Gaussian surface (length = 0.80 m, diameter = 0.20 m) is drawn in an area of a non-uniform electric field, directed at all points in the ex direction (i.e. horizontal to the right). The field varies with x, but does not vary with respect to y or z. The...
8) A negative charge, if free, tries to move A) in the direction of the electric field. B) from low potential to high potential. C) from high potential to low potential. D) away from infinity. E) toward infinity. 9) Gaussian surfaces A and B enclose the same positive charge +Q. The area of Gaussian surface A is three times larger than that of Gaussian surface B. The flux of electric field through Gaussian surface A is A) nine times larger...
18a) Find the flux through the whole surface of the sphere. b) Find the magnitude and direction of E at the surface.1 Now put the same charge at the center of a spherical shell- with twice the diameter. c) Find the magnityde and direction of E at the surface.1 d) Find the flux through the whole surface of the sphere.1 e) Why is the flux the same, even though E is weaker?1 18, A particle with charge of 12.0 μC...
Please help !!!
Calculate the magnitude of the flux of a constant electric field of 5.0 NC in the z -direction through a rectangle with area 4.0 m2 in the xy plane. a. 0 b. 5.0 N-m2/C c. 10.0 N-m2/C d. 20.0 N-m/C 10. 11. A circular ring of charge of radius b has a total charge q uniformly distributed around it. The electric field at the center of the ring is a. 0 12. A solid spherical conductor has...
A flat surface of area 3.10 m2 is rotated in a
uniform electric field of magnitude E = 5.20 105 N/C.
(a) Determine the electric flux through this area when the
electric field is perpendicular to the surface.
N · m2/C
(b) Determine the electric flux through this area when the electric
field is parallel to the surface.
N · m2/C
Part A If the electric flux through a closed surface is zero, the electric field at points on that surface must be zero. True False Submit Request Answer
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