A flat surface of area 3.10 m2 is rotated in a uniform electric field of magnitude E = 5.20 105 N/C.
(a) Determine the electric flux through this area when the
electric field is perpendicular to the surface.
N · m2/C
(b) Determine the electric flux through this area when the electric
field is parallel to the surface.
N · m2/C
A flat surface of area 3.10 m2 is rotated in a uniform electric field of magnitude...
A flat surface of area 2.60 m2 is rotated in a uniform electric field of magnitude E-5.90 x 105 N/C. (a) Determine the electric flux through this area when the electric field is perpendicular to the surface. The correct answer is not zero. N m2/C (b) Determine the electric flux through this area when the electric field is parallel to the surface. 15 34 Your response differs significantly from the correct answer. Rework your solution from the beginning and check...
9 -2 points SerPSET9 24 P001 Aflat surface of area 2.60 m2 is rotated in a uniform electric field of magnitude E = 5.90 x 10s NC (a) Determine the electric flux through this area when the electric field is perpendicular to the surface (b) Determine the electric flux through this area when the electric field is parallel to the surface.
A flat surface with area of 7.00 m2 is oriented at an angle q to a uniform electric field with magnitude 6.0 × 105 N/C. If the flux through this surface is 2.0 × 106 N×m2/C, what is q? 81.8° 32.9° 6.18° 61.6°
A loop of diameter 16 cm is placed in a uniform electric field of magnitude 4.9 102 N/C. (a) What is the electric flux through the loop when the electric field is perpendicular to the plane of the loop? N?m2/C (b) What is the electric flux through the loop when the electric field is 45? from the plane of the loop? N?m2/C (c) What is the electric flux through the loop when the electric field is parallel to the plane...
A square surface of area 5 cm2 is in a space of uniform electric field of magnitude 104 N/C . The amount of flux through it depends on how the square is oriented relative to the direction of the electric field. Find the electric flux (in N · m2/C) through the square, when the normal to it makes the following angles with the electric field. Note that these angles can also be given as 180° + θ. (Enter the magnitudes.)...
An electric flux of 143 N.m2/C passes through a flat horizontal surface that has an area of 0.62 m2. The flux is due to a uniform electric field. What is the magnitude of the electric field if the field points 15o above the horizontal?
A 44.0-cm-diameter circular loop is rotated in a uniform electric field until the position of maximum electric flux is found. The flux in this position is measured to be 6.00 105 N · m2/C. What is the magnitude of the electric field?
A flat surface with area 0.14m^2 lies in the x-y plane, in a uniform electric field given by E= 5.1i^+2.1j^+3.5k^ kN/C. find the flux through this surface
An electric flux of 157 N·m2/C passes through a flat horizontal surface that has an area of 0.72 m2. The flux is due to a uniform electric field. What is the magnitude of the electric field if the field points 15° above the horizontal? Submit Answer Tries 0/5
The figure below shows a uniform electric field of magnitude E = 440 N/C making an angle of ϕ = 61.0° with a flat surface of area A = 3.60 sq.m. What is the magnitude of the electric flux through this surface (in N · m sq./C)?