A square surface of area 5 cm2 is in a space of uniform electric field of magnitude 104 N/C . The amount of flux through it depends on how the square is oriented relative to the direction of the electric field. Find the electric flux (in N · m2/C) through the square, when the normal to it makes the following angles with the electric field. Note that these angles can also be given as 180° + θ. (Enter the magnitudes.)
(a) 49° -1.50296271872 Incorrect: Your answer is incorrect. N · m2/C
(b) 90° 0 Correct: Your answer is correct. N · m2/C
(c) 0° 5 Correct: Your answer is correct. N · m2/C
A square surface of area 5 cm2 is in a space of uniform electric field of...
A flat surface of area 2.60 m2 is rotated in a uniform electric field of magnitude E-5.90 x 105 N/C. (a) Determine the electric flux through this area when the electric field is perpendicular to the surface. The correct answer is not zero. N m2/C (b) Determine the electric flux through this area when the electric field is parallel to the surface. 15 34 Your response differs significantly from the correct answer. Rework your solution from the beginning and check...
An uniform electric field, E with a magnitude of Eo passes through a square surface at an angle of θ-56.7 degrees relative to a line on the surface, as shown in the figure below. The square measures 2m × 2m , and the flux through the surface is measured to be 23.6N.m^, What is the magnitude of the electric field, E)?
A square sheet with sides 3.05 meters long is held in a uniform electric field of magnitude 1.1×104 N/C. The sheet is oriented at an angle of 60° to the electric field direction (that is, the surface normal vector for the flat slide of the sheet makes a 60° angle relative to the electric field vector). What is the electric flux through the sheet ? Answer is in _____x10^4 Nm^2/C.
Suppose a square surface of side 0.10 m is placed in a uniform electric field of magnitude 50.0 N/C. If the angle between the field and the normal to the surface is 25.0°, what is the magnitude of the electric flux through the surface? O 4.5 Nm2/c O 0.45 N-m2/c o.50 N-m2/c o.21 N-m2/c
A uniform electric field measured over a square surface with side length d = 13.5 cm makes an angle θ = 67.50 with a line normal to that surface, as shown in the figure below. If the net flux through the square is 5.30 N·m2/C, what is the magnitude E of the electric field (in N/C)? N/C
A flat piece of cardboard with area 29.0 cm2 is immersed in a uniform electric field of strength 1.40×103 N/C. If the angle between the field and the cardboard’s area vector is 56.0°, find the electric flux through the cardboard.
An uniform electric field, E. with a magnitude of passes through a square surface at an angle of α-32.5 degrees relative to a line on the surface, as shown in the figure below. The square measures 2m x 2m, and the flux through the surface is measured to be 21.4 What is the magnitude of the electric field, Eo? N-m
A flat surface of area 3.10 m2 is rotated in a uniform electric field of magnitude E = 5.20 105 N/C. (a) Determine the electric flux through this area when the electric field is perpendicular to the surface. N · m2/C (b) Determine the electric flux through this area when the electric field is parallel to the surface. N · m2/C
An uniform electric field, E with a magnitude of Eo N passes through a square surface at an angle of a 41.1 degrees relative to a line on the surface, as shown in the figure below. The square measures 2m × 2m, and the flux through the surface is measured to be 24.72 m, what is the magnitude of a the electric field, Eo?
An uniform electric field, E with a magnitude of E passes through a square surface at an angle of α 53.0 degrees relative to a line on the surface, as shown in the figure below. The square measures 2m x 2m, and the flux through the surface is measured to be 19.7Vm*. What is the magnitude of the electric field, Eo? N-m A metal spork (half spoon, half fork) carries a net positive charge of +Q, which is distributed across...