A system has RAM access time of 10 ns, and average page fault service time of...
A system has RAM access time of 10 ns, and average page fault service time of 50 ms. If page faults occur in 2% of all accesses, what is the Mean Effective Access Time? (In ns)
Homework Answers
p = 0.02 memory access time = 10ns page fault time = 50ms = 50000000 ns effective access time=(1-p)*memory access time+p*page-fault-time = (1-0.02) * 50000000 + 0.02 * 10 = 49000000.2 ns so, average effective access time is 49000000.2 ns Answer: 49000000.2 nano-seconds.
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A system has RAM access time of 10 ns, and average page fault
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