Suppose you’re given there is a memory access timeof 356 nanoseconds and an average page-fault servicetime...
Suppose you’re given there is a memory access timeof 356 nanoseconds and an average page-fault servicetime of 5milliseconds.a.If one access out of 100causes a page fault, what will be the Effective Access Time? b.How does this compare to main memory access time?
Homework Answers
Effective access time = (1-p)*memory access time + p*page fault time
Given memory access time = 356 nano seconds
given average page fault-service time = 5 milliseconds.
Given one access out of 100 causes a page fault i.e,
page fault rate =1/100=0.01
Effective memory access time = (1-0.01)*(356*10^-9) + (0.01)*(5*10^-2)
=0.0005003
= 5.35 micro seconds
B)if the effective memory time (5.35 microseconds) compared to memory access time(356 nano seconds) then effective memory time is 1.5 times greater than memory access time
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