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Question 17 5 pts Assume we have primary memory access time of 82 nanoseconds, and a solid state disk with which memory acces
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Answer #1

Given,

Primary Memory Access Time (Tpma) = 82ns

Memory Access Time on Swap (Tsma) = 107ns

Page Fault Rate (Rf) = 0.07.

The Effective Memory Access Time formaulae is given below

Effective Memory Access Time (Tema) = ((1-Rf) Tpma)+( Re x Tsma)

Substituting the values,

Tema = [((1 – 0.07)x 82n) + (0.07 x 107n) Seconds

Tema = [((0.93)x 82n) + (0.07 x 107n) Seconds

Tema = |(76.26n) + (7.49n) Seconds

Tema = 83.75 nanoseconds

Tema = 83.75 nanoseconds

So the Effective Memory Access Time is 83.75ns.

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