Area , A = 0.135^2 m^2
theta = 67.5 degree
let the electric field is E
electric flux = E * A * cos(theta)
5.80 = E * 0.135^2 * cos(67.5 degree)
solving for E
E = 831.6 N/C
the electric field is 831.6 N/C
A uniform electric field measured over a square surface with side length d = 13.5 cm...
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Take that normal to define outward direction for the surface.
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Normal 350
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There is an electric flux of 25.5 N*m2/C through the square
region shown in the figure to the right. Each side of the square
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feta= 61 degrees relative to the plane of the surface. Assuming
that the field is uniform over the region shown, what is the
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There is an electric flux of 25.5 N*m^2/C through the square region shown...
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