Question

There is an electric flux of 25.5 N*m2/C through the square region shown in the figure to the right. Each side of the square has a length of .100 m, and the electric field is at an angle of feta= 61 degrees relative to the plane of the surface. Assuming that the field is uniform over the region shown, what is the magnitude of the electric field?

There is an electric flux of 25.5 N*m^2/C through the square region shown in the figure to the right. Each side of the square has a length of 0.100 m, and the electric field is at an angle of Theta= 61.0 degree relative to the plane of the surface. Assuming that the field is uniform over the region shown, what is the magnitude of the electric field? Number N/C

Answer 1

Electric flux , $\phi$ = 25.5 Nm²/C

side of square = a = 0.1 m

area of square is given as :

A = a² = 0.1² = 0.01 m²

The formula for electric flux is

$\phi$ = E .A cos $\alpha$                             $\alpha$ = angle between E and normal to the plane

$\theta$ = angle of E relative to plane = 61

$\alpha$ = 90 - $\theta$ = 90 - 61 = 29

inserting the values in the above formula

25.5 Nm²/C = E (0.01 m² ) Cos29

E = 2915.5 N/C