The square surface shown has a side length of 3.9 mm. It is in a
uniform electric field with a magnitude of 1925 N/C, which makes an
angle of 44.0 degrees with a normal to the square surface as shown.
Take that normal to define outward direction for the surface.
Calculate the electric flux through the surface.
Homework Answers
Area of a square
A=s2=(3.9*10-3)2=1.521*10-5 m2
The electric flux through the surface is given by
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