A 44.0-cm-diameter circular loop is rotated in a uniform electric field until the position of maximum...
A 44.0-cm-diameter circular loop is rotated in a uniform electric field until the position of maximum electric flux is found. The flux in this position is measured to be 6.00 105 N · m2/C. What is the magnitude of the electric field?
Homework Answers
SOLUTION:
Given that:
Diameter of the circular loop, d = 44 cm
Therefore, Radius of the loop, R = d/2 = 22 cm = 0.22 m
Hence, Area (A) of the loop is given by:
Therefore, Magnitude of electric field (E) is given by:
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