φ = 143 N.m2/C, A = 0.62 m2, θ = 15o
find E
φ =
EAsinθ, ∴E = φ/(Asinθ) = 891 N/C
An electric flux of 143 N.m2/C passes through a flat horizontal surface that has an area...
An electric flux of 157 N·m2/C passes through a flat horizontal surface that has an area of 0.72 m2. The flux is due to a uniform electric field. What is the magnitude of the electric field if the field points 15° above the horizontal? Submit Answer Tries 0/5
Course Contents » ... » Homework 03 » Flux Above Surface An electric flux of 159 N.m2/C passes through a flat horizontal surface that has an area of 0.77 m2. The flux is due to a uniform electric field. What is the magnitude of the electric field if the field points 15o above the horizontal?
A flat surface of area 3.10 m2 is rotated in a uniform electric field of magnitude E = 5.20 105 N/C. (a) Determine the electric flux through this area when the electric field is perpendicular to the surface. N · m2/C (b) Determine the electric flux through this area when the electric field is parallel to the surface. N · m2/C
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The electric flux from a uniform field through a flat surface is 7.80 N·m2/C when the field lines make an angle of 13.0º with the plane of the surface. What is the electric flux when the angle is changed to 77.0º? (Enter units as Nm^2/C or Vm
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An uniform electric field, E with a magnitude of E passes through a square surface at an angle of α 53.0 degrees relative to a line on the surface, as shown in the figure below. The square measures 2m x 2m, and the flux through the surface is measured to be 19.7Vm*. What is the magnitude of the electric field, Eo? N-m A metal spork (half spoon, half fork) carries a net positive charge of +Q, which is distributed across...
An uniform electric field, E. with a magnitude of passes through a square surface at an angle of α-32.5 degrees relative to a line on the surface, as shown in the figure below. The square measures 2m x 2m, and the flux through the surface is measured to be 21.4 What is the magnitude of the electric field, Eo? N-m
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