Question

An electric flux of 157 N·m2/C passes through a flat horizontal surface that has an area of 0.72 m2. The flux is due to a uni
0 0
Add a comment Improve this question Transcribed image text
Answer #1

solmo Electric flur (0)=EA Oso where Q=157 Nom% A = Area=0.72m² E = electric field = ? = Angle between electric Field directi

Add a comment
Know the answer?
Add Answer to:
An electric flux of 157 N·m2/C passes through a flat horizontal surface that has an area...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • An electric flux of 143 N.m2/C passes through a flat horizontal surface that has an area...

    An electric flux of 143 N.m2/C passes through a flat horizontal surface that has an area of 0.62 m2. The flux is due to a uniform electric field. What is the magnitude of the electric field if the field points 15o above the horizontal?

  • Course Contents » ... » Homework 03 » Flux Above Surface An electric flux of 159...

    Course Contents » ... » Homework 03 » Flux Above Surface An electric flux of 159 N.m2/C passes through a flat horizontal surface that has an area of 0.77 m2. The flux is due to a uniform electric field. What is the magnitude of the electric field if the field points 15o above the horizontal?

  • A flat surface of area 2.60 m2 is rotated in a uniform electric field of magnitude...

    A flat surface of area 2.60 m2 is rotated in a uniform electric field of magnitude E-5.90 x 105 N/C. (a) Determine the electric flux through this area when the electric field is perpendicular to the surface. The correct answer is not zero. N m2/C (b) Determine the electric flux through this area when the electric field is parallel to the surface. 15 34 Your response differs significantly from the correct answer. Rework your solution from the beginning and check...

  • A flat surface of area 3.10 m2 is rotated in a uniform electric field of magnitude...

    A flat surface of area 3.10 m2 is rotated in a uniform electric field of magnitude E = 5.20 105 N/C. (a) Determine the electric flux through this area when the electric field is perpendicular to the surface. N · m2/C (b) Determine the electric flux through this area when the electric field is parallel to the surface. N · m2/C

  • The electric flux from a uniform field through a flat surface is 7.80 N·m2/C when the...

    The electric flux from a uniform field through a flat surface is 7.80 N·m2/C when the field lines make an angle of 13.0º with the plane of the surface. What is the electric flux when the angle is changed to 77.0º? (Enter units as Nm^2/C or Vm

  • Two flat surfaces are exposed to a uniform, horizontal magnetic field of magnitude 0.46 T. When...

    Two flat surfaces are exposed to a uniform, horizontal magnetic field of magnitude 0.46 T. When viewed edge-on, the first surface is tilted at an angle of 14° from the horizontal, and a net magnetic flux of 8.50 x 10-3 Wb passes through it. The same net magnetic flux passes through the second surface. (a) Determine the area of the first surface. m2 (b) Find the smallest possible value for the area of the second surface. m2

  • A flat surface with area of 7.00 m2 is oriented at an angle q to a...

    A flat surface with area of 7.00 m2 is oriented at an angle q to a uniform electric field with magnitude 6.0 × 105 N/C. If the flux through this surface is 2.0 × 106 N×m2/C, what is q? 81.8° 32.9° 6.18° 61.6°

  • (a) The electric field in a certain region is E (4.0)) N/C. Determine the electric flux...

    (a) The electric field in a certain region is E (4.0)) N/C. Determine the electric flux due to this freld through an area represented by the vector A (1.51-7.k) m 29 How is the flux defined in terms of the electric field vector, and the area vector? Review dot product rules. N·m2/C (b) Determine the flux due to the same electric field when the surface orientation has changed such that the area is now represented by the vector A -(1.51-7.3)...

  • A flat surface with area of 7.00 m 2 is oriented at an angle to a...

    A flat surface with area of 7.00 m 2 is oriented at an angle to a uniform electric field with magnitude 6.0 x 10-NC. If the flux through this surface is 2.0 x100N.m2 C, what is 8 ? 32.99 81.89 61.6 6.180 Charges 9. 9, and -9 are placed on the x-axis at x = 0, X = 4 m, and x = 6 m, respectively. At which of the following points does the electric field have the greatest magnitude?...

  • An uniform electric field, E with a magnitude of E passes through a square surface at...

    An uniform electric field, E with a magnitude of E passes through a square surface at an angle of α 53.0 degrees relative to a line on the surface, as shown in the figure below. The square measures 2m x 2m, and the flux through the surface is measured to be 19.7Vm*. What is the magnitude of the electric field, Eo? N-m A metal spork (half spoon, half fork) carries a net positive charge of +Q, which is distributed across...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT