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A flat surface with area of 7.00 m 2 is oriented at an angle to a...
A flat surface with area of 7.00 m2 is oriented at an angle q to a...
A flat surface with area of 7.00 m2 is oriented at an angle q to a uniform electric field with magnitude 6.0 × 105 N/C. If the flux through this surface is 2.0 × 106 N×m2/C, what is q? 81.8° 32.9° 6.18° 61.6°
A flat sheet of paper of area 0.235 m2 is oriented so that the normal to...
A flat sheet of paper of area 0.235 m2 is oriented so that the normal to the sheet is at an angle of 56∘ to a uniform electric field of magnitude 12 N/C. a. Find the magnitude of the electric flux through the sheet. b. Does the answer to part A depend on the shape of the sheet? c. For what angle ϕ between the normal to the sheet and the electric field is the magnitude of the flux through...
A flat sheet of paper of area 0.140 m2 is oriented so that the normal to...
A flat sheet of paper of area 0.140 m2 is oriented so that the normal to the sheet is at an angle of 68 ∘ to a uniform electric field of magnitude 18 N/C . Part A. Find the magnitude of the electric flux through the sheet. Part B. Does the answer to part A depend on the shape of the sheet? Part C. For what angle ϕ between the normal to the sheet and the electric field is the...
9 -2 points SerPSET9 24 P001 Aflat surface of area 2.60 m2 is rotated in a...
9 -2 points SerPSET9 24 P001 Aflat surface of area 2.60 m2 is rotated in a uniform electric field of magnitude E = 5.90 x 10s NC (a) Determine the electric flux through this area when the electric field is perpendicular to the surface (b) Determine the electric flux through this area when the electric field is parallel to the surface.
A flat surface of area 3.10 m2 is rotated in a uniform electric field of magnitude...
A flat surface of area 3.10 m2 is rotated in a
uniform electric field of magnitude E = 5.20 105 N/C.
(a) Determine the electric flux through this area when the
electric field is perpendicular to the surface.
N · m2/C
(b) Determine the electric flux through this area when the electric
field is parallel to the surface.
N · m2/C
A flat surface of area 2.60 m2 is rotated in a uniform electric field of magnitude...
A flat surface of area 2.60 m2 is rotated in a uniform electric field of magnitude E-5.90 x 105 N/C. (a) Determine the electric flux through this area when the electric field is perpendicular to the surface. The correct answer is not zero. N m2/C (b) Determine the electric flux through this area when the electric field is parallel to the surface. 15 34 Your response differs significantly from the correct answer. Rework your solution from the beginning and check...
An electric flux of 143 N.m2/C passes through a flat horizontal surface that has an area...
An electric flux of 143 N.m2/C passes through a flat horizontal surface that has an area of 0.62 m2. The flux is due to a uniform electric field. What is the magnitude of the electric field if the field points 15o above the horizontal?
8) A Gaussian spherical surface of radius 0.20 m completely surrounds a collection of charges. A...
8) A Gaussian spherical surface of radius 0.20 m completely surrounds a collection of charges. A uniform electric field emerging from the charges has a value of.51 NC. a) Find the electric flux through the surface if the collection consists of a single charge. Use the Gauss Law to determine the magnitude of this charge inside the sphere. b)
An electric flux of 157 N·m2/C passes through a flat horizontal surface that has an area...
An electric flux of 157 N·m2/C passes through a flat horizontal surface that has an area of 0.72 m2. The flux is due to a uniform electric field. What is the magnitude of the electric field if the field points 15° above the horizontal? Submit Answer Tries 0/5
A flat surface with area 0.14m^2 lies in the x-y plane, in a uniform electric field...
A flat surface with area 0.14m^2 lies in the x-y plane, in a uniform electric field given by E= 5.1i^+2.1j^+3.5k^ kN/C. find the flux through this surface
9 -2 points SerPSET9 24 P001 Aflat surface of area 2.60 m2 is rotated in a uniform electric field of magnitude E = 5.90 x 10s NC (a) Determine the electric flux through this area when the electric field is perpendicular to the surface (b) Determine the electric flux through this area when the electric field is parallel to the surface.
A flat surface of area 3.10 m2 is rotated in a
uniform electric field of magnitude E = 5.20 105 N/C.
(a) Determine the electric flux through this area when the
electric field is perpendicular to the surface.
N · m2/C
(b) Determine the electric flux through this area when the electric
field is parallel to the surface.
N · m2/C
A flat surface of area 2.60 m2 is rotated in a uniform electric field of magnitude E-5.90 x 105 N/C. (a) Determine the electric flux through this area when the electric field is perpendicular to the surface. The correct answer is not zero. N m2/C (b) Determine the electric flux through this area when the electric field is parallel to the surface. 15 34 Your response differs significantly from the correct answer. Rework your solution from the beginning and check...
8) A Gaussian spherical surface of radius 0.20 m completely surrounds a collection of charges. A uniform electric field emerging from the charges has a value of.51 NC. a) Find the electric flux through the surface if the collection consists of a single charge. Use the Gauss Law to determine the magnitude of this charge inside the sphere. b)
An electric flux of 157 N·m2/C passes through a flat horizontal surface that has an area of 0.72 m2. The flux is due to a uniform electric field. What is the magnitude of the electric field if the field points 15° above the horizontal? Submit Answer Tries 0/5
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