A flat surface with area 0.14m^2 lies in the x-y plane, in a uniform electric field...
Homework Answers
Flux = ∫E dA = E·A = EA cos(θ)
Since the surface lies in the xy-plane, it's area vector is pointed in the z-direction, so only the z-component of the electric field contributes to the flux.
Flux = E·A = (5.1, 2.1, 3.5)kN/C · (0, 0, 0.14) m2 = 490. N m2 / C
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A flat surface with area 0.14m^2 lies in the x-y plane, in a uniform electric field...
Step 2: finding the flux
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(a) Determine the electric flux through this area when the
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(b) Determine the electric flux through this area when the electric
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