The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.955 g and a standard deviation of 0.305 g. Find the probability of randomly selecting a cigarette with 0.62 g of nicotine or less. P(X < 0.62 g) = Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
Solution :
Given that ,
mean =
= 0.955
standard deviation =
= 0.305
P(x < 0.62) = P[(x -
) /
< (0.62 - 0.955) / 0.305]
= P(z < -1.098)
= 0.1361
Probability = 0.1361
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