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The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean...

The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.943 g and a standard deviation of 0.301 g. Find the probability of randomly selecting a cigarette with 0.642 g of nicotine or less. P(X < 0.642 g) =

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Answer #2

To solve this problem, we need to standardize the value 0.642 g using the given mean and standard deviation of the distribution:

z = (0.642 - 0.943) / 0.301 z = -0.999

Using a standard normal distribution table or calculator, we can find the probability of a standard normal variable being less than -0.999:

P(Z < -0.999) = 0.1587

Therefore, the probability of randomly selecting a cigarette with 0.642 g of nicotine or less is 0.1587.


answered by: Hydra Master
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