A bear runs at John with a velocity of 12m/s. John stops the bear by pushing on it for 2 seconds in a motion opposing the bear’s. If the bear weighs 200kg, what average force is needed to stop the bear?
Answer: -1200N
The answer is given, but I would like to know how to do this problem.
Solution)
Given,
Initial velocity, u=12 m/s
Time, t=2 sec
Mass, m=200 kg
Final velocity, v=0
We know,
Average Force, F=m(v-u)/t
Substitute values,
F=200*(0-12)/2= -1200 N (Ans)
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