Question

3. [Ti(H20)6]3+ is an octahedral complex. (9 pts) a. Name this complex. b. How many d electrons does it have? C. Sketch the d-orbital diagram for the complex. Label the energy levels (tzg and eg) and each of the d-orbitals. d. A. is 3.99 x 10-19) (per photon). What is the value of A, in kJ/mol? e. Calculate the wavelength of light (nm) needed to excite an electron from the tz, to the eg orbital. f. What color of the visible region of the spectrum does this wavelength correlate to? g. What is this value of A, in wavenumbers (cm')? h. What color would you expect this complex to appear? (Consider the wavelength of light absorbed and whether we see this light). i. Sketch a diagram of this complex.

Answer 1

T. no of igano 6(he om(®] Aame igand-20 aqua heza nquatinnfumli ion TUPAC NANE T3f3d d onhlal of d e So no Cogp 4Eh ay cenhe Eneng for holon : 3. 99 x 10- /9j 6-023 x023 x3.99x /0J 240 32 kJot hphret constant '6G26 3/s We Know 4E also 4E 3xio8 ms 3.99 xlo9 6.6.26x10 36 75 x 3xio8m/s 6C2GX034 fsa 3m/r : /.98ro 3.99wO7 3.99 xo 4.982 x10 498-2 x11 -f498-2mm 3+ Scanned w CamScanner

f as the wavelength is 498.2 nm and from colour wheel we see the green colour corerlated to this wavelength

750400 nnometers RED VIOLET 620 430 ORANGE BLUE 490 YELLOW GREEN, 580 560

g.

where wavenumber f=1/$\lambda$ ( $\lambda$ in units of   cm

we have = 498.2 nm=498.2 *10^-9 m=  498.2 *10^-9 100 cm = 498.2 *10^-7 cm​​​​​​​ [1m =100cm]

wavenumber f=1/$\lambda$

wavenumber f=1/498.2 *10^-7​​​ cm

f= 20072.26 cm^-1

$\Delta$₀ in wavwnumber =20072.26 cm^-1

h. colour absorbed will be green

colour seen will be complementary colour of green from the wheel we see the complementary coloue of green is red

so we see red colour