Question

Let the random variable X have a continuous uniform distribution with a minimum value of 115 and a maximum value of 165. What is P(x > 120.20 X < 159.28) ? Round your response to at least 3 decimal places. Number

Answer 1

Bayes' Theorem: P(A | B) = P(A & B) / P(B)

P(X > 120.20 | X < 159.28) = P(120.2 < X < 159.28) / P(X M 159.28)

= (159.28 - 120.2)/(159.28 - 115)

= 0.883

The following statements are true

• In a normal distribution, the mean and median are equal.
• If Z is a standard normal random variable, P(Z > 41278) is very close to 0
• The normal distribution is symmetric about the mean mu