Question

given:

- 4.0% by mass of ammonium chloride

- 1.75kg of the solution

An aqueous solution is to be prepared that will be 4.0% by mass ammonium Chloride. What mass of ammonium Chloride AND what mass of water will be needed to prepare 1.7516 (kilograms of this Solution?

Answer 1

SOLUTION:

For a Binary solution(a solution containing two components),

% of Mass =(Mass of solute /Mass of solvent) *100

Here ,

NH₄Cl is solute & water is solvent .

Simply 4% by mass means the solution contains 4% NH₄Cl of its total mass .Rest will be the mass of water.

Now ,

Given mass of solution =1.75 kg

Then , Mass of NH₄Cl = 4% of 1.75 kg

= (1.75*4)/100

=0.07 kg

Now ,Mass of water required =1.75 ^_ 0.07

=1.68 kg

So, Mass of NH₄Cl required =0.07 kg

Mass of water required =1.68 kg