19)
H0: µA= µB= µC
H1: Not all the means are equal
ANOVA
Annual returns |
|||||
Sum of Squares |
df |
Mean Square |
F |
Sig. |
|
Between Groups |
34.433 |
2 |
17.217 |
2.422 |
.131 |
Within Groups |
85.300 |
12 |
7.108 |
||
Total |
119.733 |
14 |
Conclusion:
The p-value of one way analysis is 0.131. This is greater than 0.05. Thus we accept H0 at 5% level of significance and conclude that the average annual returns from the three categories of unit trust are the same.
Statement-1: Incorrect
Answer: The SSE=85.300
Statement-2: Incorrect
Answer: MST= 17.217
Statement-3: Incorrect
Answer: MSE= 7.108
Statement-4: Incorrect
Answer: F=2.422
Statement-5: Incorrect
Answer: The null hypothesis is probably true.
QUESTION 19 A financial analyst studied the annual returns of three different categories of unit trust,...
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