Given:
Hof(CH4(g)) = -74.87 KJ/mol
Hof(O3(g)) = 142.7 KJ/mol
Hof(CO2(g)) = -393.5 KJ/mol
Hof(H2O(g)) = -241.8 KJ/mol
Balanced chemical equation is:
3 CH4(g) + 4 O3(g) ---> 3 CO2(g) + 6 H2O(g)
ΔHo rxn = 3*Hof(CO2(g)) + 6*Hof(H2O(g)) - 3*Hof( CH4(g)) - 4*Hof(O3(g))
ΔHo rxn = 3*(-393.5) + 6*(-241.8) - 3*(-74.87) - 4*(142.7)
ΔHo rxn = -2977.5 KJ
Answer: b
20. What is the standard enthalpy change for the following reaction? 3CH.(g) + 40.(g) + 3C02(g)...
20. What is the standard enthalpy change for the following reaction? 3CH.(g) + 40,(g) - 3C02(g) + 6H2O(g) AH® (kJ/mol) CHig) - 74.87 03(g) +142.7 CO2(g) --393.5 H2O(g) -241.8 a. -2285.1 kJ b.-2977.5 kJ c. +2977.5 kJ d. +2285.1 kJ e. -3426.5 kJ
Using the standard heats of formation that follow, calculate the standard enthalpy change for the following reaction. Species ΔΗΡ(kJ/mol) CO2(g) -393.5 C2H2(g) 226.7 H2O(g)241.8
(NO(g)) = 20. Determine the enthalpy for the following reaction, given AH (NH3(g)) = -46.1 kJ/mol, AH +90.3 kJ/mol, and AH (H2O(g)) = -241.8 kJ/mol. 4NH3(g) + 502(g) → 4NO(g) + 6H2O(g) AH x = ? kJ a. -1274 kJ/mol d. -905.2 kJ/mol b. -1,996 kJ/mol e. -105.4 kJ/mol c. +1,274 kJ/mol
help asap 3. Calculate the standard enthalpy change, Hº, for the following reaction using standard enthalpies of formation. (1 point) 2C2H2(g) + 502(g) → 4CO2(g) + 2H20(1) Standard Enthalpies of Formation AH for C2H2(g) = +226.7 kJ/mol AHfor CO2(g) = -393.5 kJ/mol AH for H2O(l) = -285.8 kJ/mol
Isooctane C3H18 is a major component of gasoline. Determine the change in enthalpy for the combustion of 2.000 mol of isooctane from the following data: H2(g) + (1/2)02(g) + H2O(g) AH° = –241.8 kJ C(s) + O2(g) + CO2(g) AH° = -393.5 kJ 8C (s) + 9H2(g) → CgH 18 (1) AH° = -224.13 kJ Isooctane CgH 18 is a major component of gasoline. Determine the change in enthalpy for the combustion of 2.000 mol of isooctane from the following...
The standard enthalpy change for the combustion of 1 mole of propane is -2043.0 kJ. CzH3(g) + 5 O2(g) + 3 CO2(g) + 4H2O(g) Calculate 4, Hº for propane based on the following standard molar enthalpies of formation. molecule CO2(g) H2O(g) 4,Hº (kJ/mol-rxn) -393.5 -241.8
A scientist measures the standard enthalpy change for the following reaction to be 2752.8 kJ : 6CO2(g) + 6H2O(1) C6H12O6 + 6 O2(g) Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of CH1:05 is kJ/mol A scientist measures the standard enthalpy change for the following reaction to be 53.9 LJ: CO2(g) + H2(g)— CO(g) + H2O() Based on this value and the standard enthalpies of formation for the other...
Imported From Sa... 4. Use Hess' Law to calculate the enthalpy change (AHY) for this reaction: (12 pts.) 6C) + 6H21 309) CH120) using the following equations: A. Cw+ O2(g) → CO2(0) B. Hag) + 1/2O2(g) → H2O(g) C. CoH12O6 + 602(0)+ 6CO2(g) + 6H2O D. H2O → H2O(g) AH'= -393.5 kJ SH-241.8kJ AH = -2803.0 kJ AH = +40.71 kJ Why is this change in enthalpy given the term AHY? (3 pts.)
17. When 13.8 ml of 0.870 M lead(II) nitrate reacts with 90.0 ml of 0.777 Msodium chloride, 0.279 kJ of heat is released at constant pressure. What is Alt for this reaction? Pb(NO ) ) + 2NaCl(a) - PC(s) + 2NaNO3(aq) a 23.3 kJ b. 4 1.84 kJ d. 3.411 e. &J 18. A 1.67-g sample of solid silver reacted in excess chlorine gas to give a 2.21-g sample of pure solid AgCl. The heat given off in this reaction...
4. Use Hess' Law to calculate the enthalpy change (AHºr) for this reaction: (12 pts.) 6C(s) + 6H2(g) + 302(g) → C6H12O6(s) using the following equations: A. C(s) + O2(g) → CO2(g) B. H2(g) + 1/2O2(g) → H2O(g) C. C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O)- D. H20m) → H2O(g) AH°= -393.5 kJ AH°= -241.8kJ AH°= -2803.0 kJ AH°= +40.7 kJ C 6111260) At = AHT (66 tn 4) AH3= DH, + A M₂ A4 = A Hz - H₂...