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The 3.50 kg. 35.0-cm-diameter disk in the figure (Figure 1) spinning at 320 rpm. Part A How much friction force must the brak
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Answer #1

Here we apply equation of circular motion for constant angular acceleration and Newton's law of rotation as well as definition of torque.

2 M= 3 Soka - Diameter, L= 35 CM E Radius, R= d = 17.5cm Brake Initial angulax velocity g = 320 YPM - 1 xpm = 216_yadeel _ =>= f = 4.28 Newton / || Friction force applied by brake = 4:28N

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