Here we apply equation of circular motion for constant angular acceleration and Newton's law of rotation as well as definition of torque.
The 3.50 kg. 35.0-cm-diameter disk in the figure (Figure 1) spinning at 320 rpm. Part A...
The 3.50 kg. 35.0-cm-diameter disk in the figure (Figure 1lis spinning at 320 rpm. Part A How much friction force must the brake apply to the rim to bring the disk to a halt in 2.40 s? Express your answer with the appropriate units. HA + O ? Value Units Submit Request Answer Provide Feedback Figure < 1 of 1 > Brake
The 3.20 kg , 31.0-cm-diameter disk in the figure (Figure 1) is spinning at 310 rpm . How much friction force must the brake apply to the rim to bring the disk to a halt in 2.60 s ? Brake
The 2.5 kg, 35-cm-diameter disk in the figure is spinning at 300 rpm. Part A) How much friction force must the brake apply to the rim to bring the disk to a halt in 2.50 s?
Constants Part A A solid, uniform cylinder with mass 8.30 kg and diameter 19.0 cm is spinning with angular velocity 205 rpm on a thin, frictionless axle that passes along the cylinder axis. You design a simple friction- brake to stop the cylinder by pressing the brake against the outer rim with a normal force. The coefficient of kinetic friction between the brake and rim is 0.345. What must the applied normal force be to bring the cylinder to rest...
A grindstone in the shape of a solid disk with diameter 0.520 m and a mass of 50.0 kg is rotating at 850 rev/min . You press an axe against the rim with a normal force of 160 N (see the figure below), and the grindstone comes to rest in 8.50 s. (Figure 1) Part A Find the coefficient of kinetic friction between the axe and the grindstone. There is negligible friction in the bearings. Express your answer to three...
You need to design an industrial turntable that is 68.0 cm in diameter and has a kinetic energy of 0.290 J when turning at 35.0 rpm (rev/min). Part B If your workshop makes this turntable in the shape of a uniform solid disk, what must be its mass? Express your answer in kilograms. EVO AE ? m = kg Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining
Review Part A The axle in (Figure 1) is half the distance from the center to the rim. Suppose d 70 cm, What is the magnitude of the torque that the axle must apply to prevent the disk from rotating? N m |-17.15 Submit Previous Answers Request Answer X Incorrect: Try Again; 19 attempts remaining Provide Feedback Next > Figure 1 of 1 5.0kg 15 kg 10 kg
Constants Part A A high-speed flywheel in a motor is spinning at 500 rpm (revolutions per minute) when a power failure suddenly occurs. The flywheel has mass 39.0 kg and diameter 79.0 cm. The power is off for 25.0 s and during this time the flywheel slows due to friction in its axle bearings. During the time the power is off, the flywheel makes 150 complete revolutions. At what rate is the flywheel spinning when the power comes back on?...
A 40 g ball rolls around a 50 cm -diameter L-shaped track, shown in the figure, (Figure 1)at 50 rpm Part A What is the magnitude of the net force that the track exerts on the ball? Rolling friction can be neglected. Hint: The track exerts more than one force on the ball. Express your answer to two significant figures and include the appropriate units. I Å O a ? Fnet = Value Units Submit Previous Answers Request Answer X...
Constants| Periodic Table Part A In the figure the lower disk, of mass 430 g and radius 3.1 cm, is rotating at 180 rpm on a frictionless shaft of negligible radius. The upper disk, of mass 270 g and radius 2.5 cm, is initially not rotating. It drops freely down onto the lower disk, and frictional forces bring the two disks to a common rotational speed. (Figure 1) Find the final common frequency in rpm. Express your answer using two...