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The 3.50 kg. 35.0-cm-diameter disk in the figure (Figure 1lis spinning at 320 rpm. Part A How much friction force must the br
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fR = Ia -fR = maa (10 cm) f = mau t 0.35% 320x2Ã 3.50 x - 2 x 2 x 2040x 6 If = 4208Nv

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