Homework Answers
P(1 defective)=P(from A and 1 defective)+P(from B and 1 defective)
=0.75*5C1(0.01)1(0.99)4+0.25*5C1(0.02)1(0.98)4 =0.75*0.0480+0.25*0.0922 =0.0591
hence P(lot from vendor A given 1 defective)=P(from A and 1 defective)/P(1 defective)=0.75*0.0480/0.0591=0.6097
P(lot from vendor B given 1 defective)=P(from B and 1 defective)/P(1 defective)=0.25*0.0922/0.0591=0.3903
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