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2. 0/24 points | Previous Answers SerCP7 13.P.034 A simple pendulum is 7.00 m long. (a) What is the period of simple harmonic motion for this pendulum if it is hanging in an elevator accelerating upward at 8.00 m/s2? 1.88 X s (b) What is its period if the elevator is accelerating downward at 8.00 m/s2 2.11 (c) What is the period of simple harmonic motion for the pendulum if it is placed in a truck that is accelerating horizontally at 8.00 m/s2? 0.44 x s

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Answer #1

Time peripd of a simple pendulum is given by

T=2(pi)×(L/g)^(1÷2)

2-4 万when elaveatoi in ng alsonwand Prud S ii ac EL 9,81-8 12. 36 Aculum- In elevam sthe oppesile to the 8+4.8 mak the ham 3.94 소 a and n odded

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