Question

3. The production of acetanilide involves the treatment of aniline (an aromatic amine) with acetic anhydride. This reaction produces an amide called acetanilide and acetic acid (byproduct). The reaction is as follows: NH2 NCH acetic acid HCOCH Наслон aniline acetic anhydride acetanilide CH, C4H603 CgH9NO C2H4O2 93.139 102.09 . mol mol Since aniline is a liquid, conversion from milliliters to grams will yield the equivalence of 4.000 grams of aniline. 135.16 9 60.05 9 mol mol a. Calculate the theoretical mass of acetanilide produced when the mass of aniline used in the reaction equals to 4.000g The reaction goes 100% to completion and aniline is the limiting reagent. b. If after performing this synthesis the actual mass of acetanilide is 4.420 grams, then what is the percent yield?

Show work please!!!

Answer 1

93.13 gm of aniline gives 135.16 gm of acetanilide

Then, 4 gm of aniline will give how much of acetanilide

Amount of acetanilide obtained = (4 * 135.16) /93.13 = 5.80 gm of acetanilide will be obtained considering 100% recovery of the product

If only 4.420 gm of acetanilide is obtained then practical yield

Practical yield = (amount of product obtained / theoretical product yield)*100

= (4.420/5.80)*100 = 76.20%

Therefore percent yield of reaction will be 76.20%