Homework Answers
Actual yield of Fe = 22.7 g
Use:
% yield = actual yield * 100 / theoretical yield
93.2 = 22.7 * 100 / theoretical yield
theoretical yield = 24.36 g
Molar mass of Fe = 55.85 g/mol
mass of Fe = 24.36 g
mol of Fe = (mass)/(molar mass)
= 24.36/55.85
= 0.4362 mol
According to balanced equation
mol of Al required = moles of Fe
= 0.4362 mol
Molar mass of Al = 26.98 g/mol
mass of Al = number of mol * molar mass
= 0.4362*26.98
= 11.8 g
Answer: C
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