a. Find the pH of a solution that is 0.500 M in formic acid and 0.250...
Answer Part B please 1.000 mol of formic acid (HCOOH) and 0.500 mol of sodium formate (NaCOOH) are added to water and diluted to 1.00 L. Calculate the pH of the solution. Ka 1.77 x 10-4 (4 marks) Enough HCl is added to the above solution (with negligible volume change) to bring the [H3O] up to 0.100 M. Find the pH of the resulting solution. (5 marks)
3. Calculate the pH of a solution that contains 0.250 M HCOOH (formic acid) and 0.100 M NaCOOH (sodium formate). Given Ka = 1.8 x 10 - 4 for HCOOH. Please include the ICE table.
4. (16 Points) A) Calculate the pH of 0.250 Lof a 0.36 M Formic acid HCO2H and 0-30 M Sodium formate, NaCO, buffer. Assume that volume remains constant (K, for HCOH = 1.8 x 10^). B) Calculate the ph of the above buffer after the addition of a) 0.0050 mol of NaOH and b)0.0050 mol of HCI 5. (12 Points) a)Calculate the pH of 100.0 mL 0.20 M NH (K = 1.8 X 105). b)Calculate the pH of a solution...
Formic acid (HCO2H) has a Ka value of 1.70 X 10-4 at 25°C. Calculate the pH at 25°C of . . . . a. a solution formed by adding 15.0 g of formic acid and 30.0 g of sodium formate (NaCO2H) to enough water to form 0.500 L of solution. b. a solution formed by mixing 30.0 mL of 0.250 M HCO2H and 25.0 mL of 0.200 M NaCO2H and diluting the total volume to 250 mL. c. a solution...
(4) 6 pts. A buffer contains 0.500 M of Formic acid (HCHO,) and 0.500 M of sodium formate (NaCHO2). Formic acid is a weak acid that dissociates in water as following: HCHO2 (aq) + H20 (1) =H30+ (aq) + CHO2 (ag) The equilibrium constant: Ks = ([H30+1X[CH02:])/[HCH02] =1.8 x 10-4 Calculate the pH of the buffer solution.
24. (25 points) A buffer solution was prepared by dissolving 0.500 mol formic acid and 0.060 mol sodium formate in enough water to make 1 L of solution, K, for formic acid is 1.80 x 104 a) Calculate the pH of the solution. b) If this solution was diluted to 10 times its volume, what would be the pH.
a) Calculate the pH of 0.500 L of a buffer solution that contains 0.200 M of benzoic acid C6H5CO2H and 0.100 M sodium benzoate NaC6H5CO2. Ka = 6.3 x 10-5. b) Calculate the pH after .10 mL of 1.00 M H+ has been added. c) Calculate the pH after 10 mL of 1.00 M OH- has been added.
A solution is prepared by dissolving 0.23 mol of formic acid and 0.27 mol of sodium formate in water sufficient to yield 1.00 L of solution. The addition of 0.05 mol of NaOH to this buffer solution causes the pH to increase slightly. The pH does not increase drastically because the NaOH reacts with the present in the buffer solution. The K, of formic acid is 1.8 x 10+ A formic acid B. sodium formate C water D. sodium E....
QUESTION 3 To make a buffer of formic acid (Ka = 1.8 x 10-4) with a pH = 4.00, what ratio of formic acid to sodium formate is required? (Notice that I am asking for the ratio of acid to base, not base to acid!) a) 1.25 b) 0.56 c) 0.82 d) 1.87 QUESTION 4 If you find that you need an acid to base ratio of 4.23 and you are using 50.00mL of a 1.00M acid solution, what volume...
Calculate the pH of a buffer solution that is 0.30 M formic acid (HCO2H) and 0.50 M sodium formate (HCO2Na). Ka of HCO2H is 1.8 x 10-4