1) A 20.0 mL sample of lactic acid (monoprotic with Ka = 1.37 x 10-4) requires...
1) A 20.0 mL sample of lactic acid (monoprotic with Ka = 1.37 x 10-4) requires 30.0 mL of 0.200 M NaOH for titration to the equivalence point. What is the concentration of the lactic acid solution?
1.0.120 M 2. 0.200 M 3. 0.300 M
4. 6.00 x 10-3 M 5. cannot be found without the molar mass of lactic acid.
2)
Oxalic acid is diprotic with pKa1 = 1.23 and pKa2 = 4.19. What is pKb for the hydrogen oxalate ion?
1. 1.23 2. 4.19 3. 7.00 4. 9.81 5. 12.77
Homework Answers
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1) A 20.0 mL sample of lactic acid (monoprotic with Ka
= 1.37 x 10-4) requires...
Answer is NOT 1.8 x 10^-4 See Periodic Table D See Hint The leaves of the...
Answer is NOT 1.8 x 10^-4
See Periodic Table D See Hint The leaves of the rhubarb plant contain high concentrations of diprotic oxalic acid (HOOCCOOH) and must be removed before the stems are used to make rhubarb pie. If pka1 = 1.23 and pka2 = 4.19, what is the pH of a 0.0228 M solution of oxalic acid? 13.99
Benxoic acid, C7H5O2H is a weak monoprotic acid (Ka = 6.3 * 10-5). Consider a titration...
Benxoic acid, C7H5O2H is a weak monoprotic acid (Ka = 6.3 * 10-5). Consider a titration between 20.0 mL of 0.100M benzoic acid solution with 0.200 M sodium hydroxide, NaOH. a.) What volume of NaOH is required to reach the equivalence point? b.) Calculate the pH of the solution at equivalence point
A.) A 20.0 mL sample of 0.0600 M carbonic acid (H2CO3) is titrated with 5.00 mL of 0.0960 M KOH...
A.) A 20.0 mL sample of 0.0600 M carbonic acid (H2CO3) is titrated with 5.00 mL of 0.0960 M KOH. What is the solution pH to the nearest hundredths place? pKa1 = 6.35 and pKa2 = 10.33. B.) A 20.0 mL sample of 0.0600 M carbonic acid (H2CO3) is titrated with 0.0960 M KOH. How many mL of titrant are required to reach the first equivalence point? C. )A 20.0 mL sample of 0.0600 M carbonic acid (H2CO3) is titrated...
Given the diprotic acids information summarized in Table 4, predict the titration volumes for the first...
Given the diprotic acids information summarized in Table 4, predict the titration volumes for the first and second equivalence points of titrations using a 0.04 M standardized NaOH reagent. Enter your predictions into the corresponding rows of Table 5. Note that these diprotic acids constitute the set of materials from which the acid unknowns were selected. Also note that superscripted numbers are source reference citations. Acid Name MW (g/mol) Solubility (g/100 mL H20) pka1 pka2 Oxalic (dihydrate) 126.07 14.3 1.23...
A sample of 0.2140 g of an unknown monoprotic acid was dissolved in 25.0 mL of...
A sample of 0.2140 g of an unknown monoprotic acid was dissolved in 25.0 mL of water and titrated with 0.0950 M NaOH. The titration required 30.0 mL of base to reach the equivalence point, at which point the pH was 8.68. a) What is the molecular weight of the acid? b) What is the pKa of the acid?
1. The equivalence point of a weak, monoprotic acid with a volume of 22.00 mL was...
1. The equivalence point of a weak, monoprotic acid with a volume of 22.00 mL was reached after adding 22.10 mL of 0.1025 M NaOH(aq) and the pH at this volume was 8.91. The pH was 3.37 when the volume of NaOH(aq) added was 11.05 mL. What is the value of Ka for this unknown acid? 0.1025 0.1030 3.37 8.91 1.23 x 10-9 4.27 x 10-4 2. A solution of acetic acid, HC2H3O2, a weak monoprotic acid, was standardized by...
1) Chloropropionic acid, ClCH2CH2COOH is a weak monoprotic acid with Ka = 7.94 x 10-5 M....
1) Chloropropionic acid, ClCH2CH2COOH is a weak monoprotic acid with Ka = 7.94 x 10-5 M. Calculate the pH at the equivalence point in a titration 40.4 mL of 0.49 M chloropropionic acid with 0.9 M KOH. 2) What is the pH after 22.90 mL of NaOH are added?
Chloropropionic acid, ClCH2CH2COOH is a weak monoprotic acid with Ka = 7.94 x 10-5M. Calculate the...
Chloropropionic acid, ClCH2CH2COOH is a weak monoprotic acid with Ka = 7.94 x 10-5M. Calculate the pH at the equivalence point in a titration 24.1 mL of 1.33 M chloropropionic acid with 0.3 M KOH.
A 20.0 mL sample of a 0.099 M monoprotic acid, HA, is titrated with 0.25 M NaOH. What volume of base is needed to reach...
A 20.0 mL sample of a 0.099 M monoprotic acid, HA, is titrated with 0.25 M NaOH. What volume of base is needed to reach the equivalence point? Report your answer to 2 decimal places.
15. A 66 mL sample of a solution of sulfuric acid, H,SO, is neutralized by 34...
15. A 66 mL sample of a solution of sulfuric acid, H,SO, is neutralized by 34 mL of a 0.13 M sodium hydroxide solution. Calculate the molarity of the sulfuric acid solution 16. If 300 mL of 3.9 M HCl is added to 400 mL of 2.9 M NaOH, what is the pH? 17. If 287 mL of 4.7 M HCl solution is added to 284 mL of 3.2 M Ba(OH), solution, what will the pH be? 18. What is...
Answer is NOT 1.8 x 10^-4
See Periodic Table D See Hint The leaves of the rhubarb plant contain high concentrations of diprotic oxalic acid (HOOCCOOH) and must be removed before the stems are used to make rhubarb pie. If pka1 = 1.23 and pka2 = 4.19, what is the pH of a 0.0228 M solution of oxalic acid? 13.99
15. A 66 mL sample of a solution of sulfuric acid, H,SO, is neutralized by 34 mL of a 0.13 M sodium hydroxide solution. Calculate the molarity of the sulfuric acid solution 16. If 300 mL of 3.9 M HCl is added to 400 mL of 2.9 M NaOH, what is the pH? 17. If 287 mL of 4.7 M HCl solution is added to 284 mL of 3.2 M Ba(OH), solution, what will the pH be? 18. What is...
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