1.
The equivalence point of a weak, monoprotic acid with a volume of 22.00 mL was reached after adding 22.10 mL of 0.1025 M NaOH(aq) and the pH at this volume was 8.91. The pH was 3.37 when the volume of NaOH(aq) added was 11.05 mL. What is the value of Ka for this unknown acid?
0.1025 |
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0.1030 |
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3.37 |
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8.91 |
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1.23 x 10-9 |
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4.27 x 10-4 |
2.
A solution of acetic acid, HC2H3O2, a weak monoprotic acid, was standardized by titration with 0.1170 M NaOH solution. If 28.37 mL of the NaOH were required to neutralize completely 12.94 mL of the acetic acid solution, what is the molarity o of the acetic acid solution?
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1. The equivalence point of a weak, monoprotic acid with a volume of 22.00 mL was...
QUESTION 1 The equivalence point of a weak, monoprotic acid with a volume of 22.00 ml was reached after adding 22.10 mL of 0.1025 M NaOH(aq) and the pH at this volume was 8.91. The pH was 3.37 when the volume of NaOH(aq) added was 11.05 mL. What is the value of Ka for this unknown acid? O 0.1025 1.23 x 10-9 0.1030 8.91 3.37 4.2710-4
QUESTION 3 A solution of acetic acid, HC2H302, a weak monoprotic acid, was standardized by titration with 0.1660 M NaOH solution. If 20.59 mL of the NaOH were required to neutralize completely 18.23 ml of the acetic acid solution, what is the molarity o of the acetic acid solution?
millimoles of NaOH titrant Chemical Equilibria: K, of a Weak Monoprotic Acid Report Form Name: Partner's Name: (if any) Lab Section MWITTHM-TH (Circle) Data and Calculations 1. Measurement of pH and titration of acetic acid solution Concentration of standardized NaOH titrant 0.1054 Mass concentration of acetic acid 2.40 - mol/L Trial 3 Measured pH of the acetic acid solution Mass of acetic acid solution taken for titration Trial 1 3.09 20.16 0 11.4 Trial 2 3.32 30.06 Initial buret reading...
Titration of a Weak Monoprotic Acid with a Strong Base Volume of Base (mL) 1. Using the graph, determine the K, of the weak acid. 2. Suppose 100mL of the monoprotic acid referred to in the graph was titrated with 1M NaOH, determine the molarity of the weak acid. The corresponding balanced chemical equation is shown below. HA + NaOH + H2O + A + Nat 3. If the weak acid above was prepared by using 5g of the weak...
50.0 mL sample of the weak acid the concentration of the weak acid = 0.15 M 25 mL of the week acid into 100 mL beaker titrated this solution of 0.21 M NaOH moles of weak acid = 3.75*10^-3 moles of NaOH = moles of week acid c) How many milliliters of the NaOH are required to neutralize the sample of weak acid? d) How many moles of NaOH have been added at one half of the volume in part...
A titration of a 75.0 mL aqueous solution of 0.12 M acetic acid, a weak, monoprotic acid with a Ka of 1.76 × 10–5, with 0.30 M NaOH is performed. What is the pH of the solution after 10.0 mL of NaOH has been added (at 25oC)? Group of answer choices 5.24 3.98 8.21 6.17 4.45
2) 19.63 mL of 0.100 M NaOH is required to neutralize 2.00 mL of a solution containing acetic acid according to the following reaction: HC2H302(aq) + NaOH(aq) → NaC2H3O2(aq) + H2O(1). How many grams of acetic acid are present in 2 mL solution? Report the correct number of significant figures, and report the units. 3) 19.63 mL of 0.100 M NaOH is required to neutralize 2.00 mL of a solution containing acetic acid according to the following reaction: HC2H3O2(aq) +...
Weak Acid Titration When a 14.0 mL sample of a monoprotic weak acid is titrated with 0.10 M NaOH, it generates the titration curve shown below. Weak Acid titrated with 0.10 M NaOH pH Volume of 0.10 M NaOH a) What is the molar concentration of the original sample of weak acid? х М b) What is the ka for this weak acid?
If the pH at the equivalence point for titration of a monoprotic weak acid with NaOH is 9.00, and 10 mL of base is required to reach the equivalence point, how would you determine the pKa of the acid? the pKa is 9.00 determine the pH after 5 mL of base is added; this is the pKa determine the pH when 20 mL of base is added; this is the pKa the pKa is -log(9)
A student peforms a titration, titrating 25.00 mL of a weak monoprotic acid, HA, with a 1.24 M solution of NaOH. They collect data, plot a titration curve and determine the values given in the below table. ml NaOH added pH Half-way Point 18.73 3.60 Equivalence point 37.45 8.59 How many moles of NaOH have been added at the equivalence point? mol What is the total volume of the solution at the equivalence point? mL During the titration the following...