Nitrogen and hydrogen combine at a high temperature, in the presence of a catalyst, to produce ammonia.
N2(g)+3H2(g)⟶2NH3(g)
Assume 0.200 mol N2 and 0.647 mol H2 are present initially.
After complete reaction, how many moles of ammonia are produced?
NH3: mol
How many moles of H2 remain?
H2: mol
How many moles of N2 remain?
N2: mol
According to the reaction,
1 mole N2 require 3 mole H2
0.200 mole N2 require 3×0.200 = 0.600 mole H2
Since we have more than this hence N2 is limiting reagent.
1 mole N2 give 2 mole NH3
0.200 mole N2 give 0.200×2 = 0.400 mole NH3
Moles of N2 remain = 0 moles
Moles of H2 remain = 0.647-0.600 = 0.047 mole
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