Question

Nitrogen and hydrogen combine at a high temperature, in the presence of a catalyst, to produce ammonia.

N2(g)+3H2(g)⟶2NH3(g)N2(g)+3H2(g)⟶2NH3(g)

Assume 0.280 mol N20.280 mol N2 and 0.880 mol H20.880 mol H2 are present initially.

After complete reaction, how many moles of ammonia are produced?

Nitrogen and hydrogen combine at a high temperature, in the presence of a catalyst, to produce ammonia. N2(g) + 3H2(g) + 2NH3

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Answer #1

N₂ + 3H2 → 2NH3 Mols of NH3 Produced: 2x noles of 2 - 2x0.280 - 10.560 mol nobs of My reacted: 3x0.280 u 0.840 mols 0.880 - 0

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