Homework Answers
it is given that volume, V = 5 L (constant)
temperature = constant (room temperature,say 250C)
in first case, O2 gas exists as diatomic gas (2 O atmos) so its molar mass = 32g/mol
no of moles, n = m/M = 5g / 32g/mol = 0.16 moles
in second case, He gas exists as monoatomic gas so its molar mass = 4g/mol
no of moles, n = m/M = 5g / 4g/mol = 1.25 moles
now ideal gas equation is, PV = nRT
as V,T,R are constants , so P is directly proportional to n (no of moles)
since 5g of He has more no of moles than 5g of O2 so He will have higher pressure (B)
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