How many moles of Zn(NO3)2 does 111.50 g equal?
A solution composed of 5.00 mL of 0.0120 M Pb(NO3)2, 3.00 mL of 0.0300 M KI, and 2.00 mL of 0.20 M KNO, is determined Spectroscopically to have [1] -6.25 x 10" M. Show all steps of your calculations. Credit will not be given if work is not shown. a). How many moles of l' is present initially? (2 pt) S+3+2=100L OIL •BM= I 19x10 noles b). How many moles of I should precipitate from the solution? (2 pt)
Homework 2 1) How many moles of Na2CO3 are there in 10.0 L of 2.00 M solution? 2) What weight (in grams) of H2SO4 would be needed to make 750,0 mL of 2.00 M solution?
A solution composed of 5.00 mL of 0.0120 M Pb(NO3)2, 3.00 mL of 0.0300 M KI, and 2.00 mL of 0.20 M KNO3 is determined spectroscopically to have [1'] = 6.25 x 10 Show all steps of your calculations. Credit will not be given if work is not shown. (2 pt) a). How many moles of l' is present initially? OIL OB S+3+2=10nL M = a. 1o-s b). How many moles of I should precipitate from the solution? " Xo...
A student mixes 41.0 mL of 2.84 M Pb(NO3)2(aq) with 20.0 mL of 0.00235 M Nal(aq). How many moles of Pbla(s) precipitate from the resulting solution? Number K,,[Pb12()] – 9810 mol What are the values of [Pb2+), [1]. [NO3-), and [Na*) after the solution has reached equilibrium at 25 °C? Number Number [Pb?*] = Number Number [no; ]- 0 M [nat)-
How many moles of nitrate ion are in 1.0 L of a 8.8 M Mg(NO3)2 solution?
How many moles of water is produced from the reaction of 15.0 ml of 2.00 M sulfuric acid with 13.5 ml of 2.00 M potassium hydroxide?
1. How many moles of Ca(NO3)2*4H2O are in 50.0 mL of 0.0906 M Ca(NO3)2*4H2O? Report your answer with 3 significant figures. Do not include units. 2. How many moles of Na3PO4*12H2O are in 50.0 mL of 0.0550 M Na3PO4*12H2O? Report your answer with 3 significant figures. Do not include units. 3. If 50.0 mL of 0.0906 M Ca(NO3)2*4H2O are reacted with 50.0 mL of 0.0550 M Na3PO4*12H2O, using the balanced chemical equation from the video, determine which is the limiting...
help! 1) How many moles of precipitate will be formed when 80.0 mL of 2.00 M NaI is reacted with 100.0 mL of 0.900 M Pb(NO₃)₂ in the following chemical reaction? 2 NaI (aq) + Pb(NO₃)₂ (aq) → PbI₂ (s) + 2 NaNO₃ (aq)
QUESTION 1 43.2 mL of aqueous 0.255 M Pb(NO3)2 is mixed with 36.1 mL of 0.415 M NaCl. The equation for the precipitate reaction is: Pb(NO3)2 (aq) + 2 NaCl (aq) --> PbCl2 (s) + 2 NaNO3 (aq) How many moles of PbCl2 are formed? (with correct sig figs) QUESTION 2 What volume (in mL!!!) of 1.28 M HCl is required to react with 3.33 g of zinc (65.41 g/mol) according to the following reaction? Zn(s) + 2 HCl (aq)...