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A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 0.04. At the checkpoint, the security system denied a person without security problems 1.5% of the time. Also the security system passed a person with security problems 1% of the time. What is the probability that a random person does not pass through the system and is without any security problems? Report answer to 3 decimal places.
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Answer #1

P(does not pass through the system and it without the security problems)

=P(without the security problems)*P(does not pass|without the security problems)

=(1-0.04)*0.015 =0.014

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