Question 5.
Solution: we know sum of n terms GP = a1( 1- rn) / (1-r)
The given series can be arranged as:
S = 30( 1/1.072 + 1/1.073 + ….1/1.0740)
= 30 (1/1.072) (1-1/1.0740) / (1-1/1.07) [ Here, a = r = 1/1.07 and n = 40]
= 30 * 0.0533
= 1.60
Question 6
Solution: We know sum of GP up to Infinity is = a1 / 1-r = 30[(1/1.072)/ (1-1/1.07) ]
= 400.53
Question 5 1.8 s-ㅛ+음+ +고ew? Round your final answer to two decimal places. Question6 1.8 s-ur...
Question 1 1I s-1+2+3 +4+... +1000-7 Question 2 1.8 s-1+3+9+27+81+...-? o 121 O None of the answers are correct o 2000 O 3000000 Infinity Question 3 1.81 s-끊+흡+습+. . . +i ..?,ound your final answer to two decimal places. Question4 s- 1+4+8+16+32+64+.. +2? O 22(281) O 1+2 (21) 1.81 O None of the answers are conect o 1 + 2' (2 +1)
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