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10. Examine the reaction: 2NOCI(g) 2NO (g) + Cl2(g) When the above reaction reaches equilibrium the...
14. For the reaction: 2NOCI(g) 2NO(g) + Club), K = 1.6 x 10. What are the equilibrium concentrations of each species it tions of each species if 1.0 mole of NOCI is initially placed in an empty 2.0 L flask? 14. For the reaction: 2NOCI(B) = 2NO(g) + Cl2(g), K = X 1.6*10 What are the equilibrium concentrations of each species if 1.0 mole of NOCI is initially placed in an empty 2.0 L flask?
5. The reaction 2NO+ Cl2 → 2NOCI is thought to occur in two steps, as shown by the following proposed mechanism: O NO + Cl2 NOCI (fast, at equilibrium) (i) NO + NOCI, → 2NOCI (slow) What rate law does this mechanism predict? Select the best choice by circling it. a. rate = ** [NO]?[NOCI] rate = *, [NO]2 C. rate = [NOCL] d. rate = kek [NO](C1,12 rate = [NO] f. rate = kaka [NO]+[C12] g. rate = kak2...
Consider the following equilibrium system at 821 K. 2NOCI(g) 2NO(g) + Cl2 (g) If an equilibrium mixture of the three gases at 821 K contains 9.34 x 103 M NOCI 3.47 x 102 M NO, and 2.57 x 10 M Cl2, what is the value of the equilibrium constant К? К We were unable to transcribe this imageConsider the following equilibrium system at 521 K 2CH2 Cl2 (g) CH4 (g)CC4 (g) If an equilibrium mixture of the three gases at...
63. At 35°C, K = 1.6 x 10-6 for the reaction 2NOCI(9) = 2NO(g) + Cl2 (9) Calculate the concentrations of all species at equilibrium for each of the following original mixtures. a. 2.0 moles of pure NOCI in a 2.0-L flask Answer b. 1.0 mole of NOCI and 1.0 mole of NO in a 1.0-L flask Answer c. 2.0 moles of NOCI and 1.0 mole of Cl, in a 1.0-L flask
Select all that apply. The rate law for the reaction 2NO(g) + Cl2(g) → 2NOCI(g) is given by R-k[NO][C121 If the following is the mechanism for the reaction, NO(g) + Cl2(g) → NOC12(g) NOCI,(g) + NO(g) → 2NOCI(g) which of the following statements accurately describes this reaction? Check all that apply. 2nd order reaction The first step is the slow step. Doubling [NO] would quadruple the rate. Cutting (Cl) in half would decrease the rate by a factor of two....
Constants 1 Pe Consider the reaction between NO and Cl2 to form NOCI: 2NO (g) + Cl2 (g) = 2NOCl (9) A reaction mixture at a certain temperature initially contains only (NO) = 0.67 Mand (Cl2] = 0.55 M . After the reaction comes to equilibrium, the concentration of NOCI is 0.34 M. Part A You may want to reference (Page 688) Section 15.6 while completing this problem. Find the value of the equilibrium constant (Kc) at this temperature. Express...
Consider the reaction: 2NO(g) + Cl2(g) → 2NOCI(g) Given the following table of thermodynamic data, Substance NO (g) Cl2(g) NOCI (g) AH (kJ/mol) 90.3 0 sº (/mol.K) 210.7 223.0 51.7 261.6 Calculate Ahºrxn and AS rxn and determine the temperature at which the reaction switches from being spontaneous to being non-spontaneous.
9. The following equilibrium is endothermic. In the box below, show how the reaction will shift response to the indicated stress by writing →., or no shift. 30,(8) 203(g) Stress Equilibrium shift? Increase O2 concentration Add heat Add a catalyst Cool reaction Benzene Bromine Bromobenzene Hydrogen bromide
At 500.0 K, gaseous NOCl decomposed to NO and Cl2 according the following reaction: 2NOCl(g) ⇌ 2NO(g) + Cl2(g) If 1.00 mole of NOCl is placed in a 1.00 liter contained, and at equilibrium, the concentration is 0.91M, what is the equilibrium constant, Kc? 4. At 500.0 K, gaseous NOCI decomposed to NO and Cl2 according the following reaction: 2NOCI(g) = 2NO(g) + Cl2(g) If 1.00 mole of NOCI is placed in a 1.00 liter contained, and at equilibrium, the...
Part A Consider the reaction between NO and Cl2 to form NOCI: 2NO (9) + Cl2 (9)=2NOCI (9) A reaction mixture at a certain temperature initially contains only (NO) = 0.60 M and (Cl) = 0.63 M. After the reaction comes to equilibrium, the concentration of NOCI is 0.22 M. You may want to reference (Page 688) Section 15.6 while completing this problem. Find the value of the equilibrium constant (K) at this temperature. Express your answer using two significant...