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7. An aqueous solution is 0.00500 M in Ca(OH). Give (OH), H 1. pH, and pOH. 8. Calculate the pH and % lonization of 0.0200 MH
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7 CaloH), Ca²+ + 2017 0-00 500 M in Colom), means C Concentration of [Ca ²+] = 0.005 m [OH-] = 2x0.005M = 0.0lom. Since we ha8) Ka = 6.8x104. o HF + H₂0 I 0.02. m C -x - E 0.02-2 H3O+ +F o +X +x. x a. + X ka = 6-8x10-4 - (H+) [p) (HF) 6.8 x 104 = x.2(9) HF + H₂O Ka F + H₂ot. PH = Pka + log (f 11 - [HA Handerson Hasselbalch Equation. ] Pka = -log ka = -log (6.8 x104) Pka =

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