The balanced equation for the decomposition of TNT, C₇ H₅(NO₂)₃, is
2 C₇ H₅(NO₂)₃(s) → 7 C(s)+7 CO(g)+3 N₂(g)+5 H₂ O(l)
How many moles of each product would form if 8.32 mol of C₇ H₅(NO₂)₃ react?
_______ mol C
_______ mol CO
_______ mol N₂
_______ mol H₂ O
From the equation, moles of C = 7 / 2 * moles of C7H5(NO2)3
= 7 / 2 * 8.32 = 29.12 moles
Moles of CO = 7 / 2 * moles of C7H5(NO2)3 = 7 / 2 * 8.32 = 29.12 moles
Moles of N2 = 3 / 2 * moles of C7H5(NO2)3 = 3 / 2 * 8.32 = 12.48 moles
Moles of H2O = 5 / 2 * moles of C7H5(NO2)3 = 2.5 * 8.32 = 20.8 moles
The balanced equation for the decomposition of TNT, C7H5(NO2)3, is 2 C7H5(NO2)3(s) → 7 C(s) + 7 CO(g) + 3 N2(g) + 5 H2O(l) How many moles of each product would form if 8.92 mol of C7H5(NO2)3 react?
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