Question

a For the following balanced chemical equation, calculate how many moles of products would be produced if 0.666 mol of the first reactant were to react completely CO (9) + 4H2(g) + CH (9) + 2H, 0(1) mol CH mol H2O b For the following balanced chemical equation, calculate how many moles of products would be produced if 0.441 mol of the first reactant were to react completely. BaCl, (aq) + 2AgNO, (aq) + 2ACI(8) + Ba(NO), (aq) mol AgCI mol Ba(NO) C For the following balanced chemical equation, calculate how many moles of products would be produced if 0.435 mol of the first reactant were to react completely C,H, () +50,() + 4H, O(1) + 300,() mol H,O mol CO d For the following balanced chemical equation, calculate how many moles of products would be produced if 0.747 mol of the first reactant were to react completely Previous 3H,SO.(aq) + 2Fe(s) Fe (SO4)3(aq) + 3H2 (9) Next

Answer 1

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3 CO₂(g) + 4H2 (9) Chylg) + 2120 (8) 1 mole of coa produces I mole of Chy and a mole of H2O 0.666 mole of log will produce 0.666 mole of Chy and 1.332 mole of H₂O.

(b) Bally (as) + 2 AgNO3 () —, e Agu (5) + Ba(NO3)2 (a). I mole of Bally produces a mole of Age and I mole of Ba(NO3)2 0.441 mole of Badly will produce 0-882 mole. f aza and 0.441 mole of Ba(NO3)2 (C) Cz Hq (g) + 502 (9) 4420 (1) + 3002 (9) 1 mole of CzHg produces 4 mole of 420 & 3 mole of col. 0.435 mole of Calg will puoduce 4X0.435 mole of H20 and 3x0.435 mole of coa = 1.74 mole of H₂O = 1.305 mole of Coq (d) 3 H2SO4 (as) + 2Fels) — Fey (504)3 (aj) + 312 [g). 3 mole of H₂SOy produces I mole of reg (504)3 and 3 mole of Hg. 0.747 mole of Hg Joy will produce + x 0.747 mole of Fog (304)3 and 3x0.747 more of Hg. = 0.249 mole of fez (504)3 = 0.747 more of H2.