When 20.0 grams of an unknown nonelectrolyte compound are dissolved in 500.0 grams of benzene, the freezing point of an unknown nonelectrolyte compound is 3.77 °C. The freezing point of pure benzene is 5.44 °C. What is the change in freezing point?
When 20.0 grams of an unknown nonelectrolyte compound are dissolved in 500.0 grams of benzene, the...
The freezing point of a solution of 1.104 g of an unknown nonelectrolyte dissolved in 36.81 g of benzene is 1.08°C. Pure benzene freezes at 5.48°C and its Kf value is 5.12°C/m. What is the molecular weight of the compound?
When 0.60 grams of a non-electrolyte unknown compound is dissolved in 10 grams of water, the freezing point of the solution is -1.86o C. Given that the freezing point of pure water is 0o C and that the freezing-point depression constant for water is 1.86 o C/mol/kg, calculate the molecular mass (g/mol) of the unknown compound.
When 12.6-grams of an unknown compound is placed in 0.116-kg of benzene, the freezing point is changed by 2.34°C. The value of Kf= 4.90°C/m for benzene. Determine the molar mass of the unknown compound. Answer to 1 decimal place and include your units. Answer: Determine the molality of a solution when 32.3 grams of ethanol, C2H5OH (Molar mass = 46.08 g/mol) is dissolved in 0.947 kg of water. Answer to 2 decimal places. Answer: Find the freezing point of a...
The freezing point of a solution that contains 1.00 g of an unknown compound, (A), dissolved in 10.0 g of benzene is found to be 2.17 oC. The freezing point of pure benzene is 5.48 oC. The molal freezing point depression constant of benzene is 5.12 oC/molal. What is the molecular weight of the unknown compound?
A 5.11 g sample of a compound is dissolved in 154.7 g of benzene. The freezing point of this solution is 1.00°C below that of pure benzene. The compound is a nonelectrolyte. What is the molar mass of this compound? K for benzene = 5.12(°C kg)/mol. (Do not include units in your answer. If you round during your calculations make sure to keep at least 3 decimal places. Report your answer to the nearest whole number.) AT=i Kh Msolute AT...
A solution made by dissolving 150.0 g of an unknown compound in 425.0 mL of benzene to make a solution which has a freezing point 18.6 °C lower than that of pure benzene. Kf for benzene is 5.12 °C/m and the density of benzene is 0.877 g/mL. b) The molality of the solution is 3.63. How many moles of the unknown compound were dissolved in the solution? C) what is the molar mass of the unknown compound?
The freezing point of benzene C6H6 is 5.50°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in benzene is testosterone . If 14.32 grams of testosterone, C19H28O2 (288.4 g/mol), are dissolved in 214.0 grams of benzene ... The molality of the solution is ____ m. The freezing point of the solution is ____ °C.
The freezing point of benzene CHs is 5.50°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in benzene is cholesterol is cholestero If 14.17 grams of cholesterol, C27H460 (386.6 g/mol), are dissolved in 209.3 grams of benzene The molality of the solution is The freezing point of the solution is m. oC
The freezing point of benzene C6H6 is 5.50°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in benzene is estrogen (estradiol). If 12.26 grams of estrogen, C18H24O2 (272.4 g/mol), are dissolved in 150.7 grams of benzene ... The molality of the solution is__________ m. The freezing point of the solution is___________ °C.
A solution was prepared by dissolving 1.846 grams of an unknown compound (nonelectrolyte) in 15.75 grams of water (Kf = 1.86 oC/m). The solution freezes at -1.50 oC. If pure water freezes at 0.00 oC, what's the molar mass of unknown compound?