A solution was prepared by dissolving 1.846 grams of an unknown compound (nonelectrolyte) in 15.75 grams of water (Kf = 1.86 oC/m). The solution freezes at -1.50 oC. If pure water freezes at 0.00 oC, what's the molar mass of unknown compound?
A solution was prepared by dissolving 1.846 grams of an unknown compound (nonelectrolyte) in 15.75 grams...
A solution prepared by dissolving 90.0 mg of a sugar (a molecular compound and a nonelectrolyte) in 1.00 g of water froze at -0.930°C. What is the molar mass of this sugar (g/mol)? The value of Kf is 1.86°C/m.
A solution prepared by dissolving 513 mg of a sugar (a molecular compound and a nonelectrolyte) in 1.00 g of water froze at -2.79 °C. What is the molar mass of this sugar? The value of Kf is 1.86°C/m. Answer in g/mol.
A solution is prepared by dissolving 3.04 g of an unknown nonelectrolyte in 16.00 g of cylcohexane (tf = 6.6 oC and kf = 20.0 oC/m). What is the molar mass of the unknown compound if the solution has a freezing point of -6.7 oC? Please see https://youtu.be/lwWZ5hdB61M for assistance. Mm = g/mol
31.)Show the calculation of the boiling point of a solution made by dissolving 15.9 grams of the nonelectrolyte C3H7OH in 350 grams of water. Kb for water is 0.51, BP of pure water is 100oC. 30.)Show the calculation of the freezing point of a solution made by dissolving 12.6 grams of the nonelectrolyte C2H5OH in 200 grams of water. Kf for water is 1.86, FP of pure water is 0oC. 29.)Show the calculation of the volume of 0.238 M solution...
Question 27 (1 point)B A solution is prepared by dissolving 4.12 grams of a nonelectrolyte in 60.0 grams of water. If the boiling point of this solution is 100.15°C, what is the molar mass of the unknown substance? 844 g/mol 851 g/mol 0.351 g/mol 1.28 g/mol 234 g/mol
A solution contains 0.180 g of an unknown nonelectrolyte solute in 50.0 g of water. The solution freezes at –0.040 0C (notice the negative sign). A) What is the molar mass of the unknown solute? B) What is the boiling temperature of the solution? Kf(water) = 1.86 K kg mol-1 ; Kb(water) = 0.51 K kg mol-1 . Assume that the solute only exists as a monomer in aqueous solution.
Determine the molar mass of an unknown non-electrolyte compound given the following data: 1.453 grams of the unknown compound is dissolved in 10.08 grams of water (Kf = 1.853 0C/m). The solution freezes at -1.47 0C. What is the molar mass of the unknown compound?
8. A solution is prepared by dissolving 0.434 moles of ethanol, C2H60, in 150. grams of water. Calculate the molality of the solution, freezing point of the solution, and boiling point of the solution. (Kf of H2O 1.86°C/m; fp of H20 = 0.00°C; Kb of H20 = 0.512°C/m; BP of H20 100.00°C)
1.A solution that contains 15.581 grams of benzene (molar mass = 78.1 g/mol) in 420 g of cyclohexane freezes at a temperature 9.50 ºC below the freezing point of pure cyclohexane. Calculate the molar freezing point depression constant, Kf, for cyclohexane. 2. The molar boiling point elevation constant for water is 0.512 ºC/m. What is the boiling point of a solution containing 673 g of water and 78.0 g of CaCl2? 3. A solution containing 32.0 g of an unknown...
Il see Periodic Table See Hint A solution prepared by dissolving 90.0 mg of a sugar (a molecular compound and a nonelectrolyte) in 1.00 g of water froze at -0.930°C. What is the molar mass of this sugar? The value of Kris 1.86°C/m. g/mol