Question

please answer and label all steps

Hydrolysis of 2-bromo-2-methylpropane (tert-butyl bromide) yields 2-methylpropan-2-ol. (сн), сон + н,о* + CH CBr 2H,O Br Give the SN1 mechanism. The reactants are already given in step 1; you need to start by adding curved arrow(s) to the reactants. For each remaining step, draw all species regardless of if they are involved in that step or not. Also, include electrons and charges where necessary. Details count Note: You should have 4 carbon atoms, 13 hydrogen atoms, 2 oxygen atoms, and a bromine atom in each drawing module. Step 1. Reactants are given - add curved arrow(s) CH3 -Нас- CHs Step 2

Answer 1

Formation of the carbocation is the characteristic of the SN₁ reaction. In the first step bromine leaves and carbocation forms.

Then water acts as nucleophile and attacks carbocation along with inversion. Finally another molecule of the water acts as base and deprotonates the intact nucleophile to form the final product.

P a CH3 Cty Bro My Carbocation By: Formation → = Nullcobhillic attack chy Clin chia Oh, Hő Hö wimbo =ts mfano H2o - Proton abstraction V by base hy for + H₂ot + Bro cha final products. cs Scanned with CamScanner