ANSWER :
The given information is
NMR signal in NMR spectra depends upon number of atoms of same type.
As in this case two types of 1H present.
Each corresponds to each compound present in mixture.
Now NMR based upon the corresponding amount of signals.
We can calculate their ratio using this formula.
molar ratio of two compounds (MA/B)=
(IntegralA/NA)/ (IntegralB/NB)
Where,
IntegralA - corrsponds to signal integral of A in spectra
NA- Number of protons of A corresponds to signal from molecular formula.
IntegralB - corrsponds to signal integral of B in soectra
NB - Number of protons of B .
Now here to solution.
MA/B = (6/9) / (1/3)
=2/1
Or 2:1
Moles of A and B is in 2:1
Now, mole percentage of each.
Let Total number of moles = 2+1 = 3
=> For A Number of moles = 2
Mole percentage of A = (2÷3) ×100 %
= 66.67%
So, Mole percentage of tert-butyl bromide = 66.67%
Now,
For B Number of moles = 1
Mole percentage = (1÷3) × 100%
= 33.33 %
So, Mole percentage of methyl bromide is 33.33%
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