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#462. Teacher Salaries Based on the 2017-2018 Average Starting Teacher Salaries by State measured by NEA, the average startin

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Answer #1

Solution :

Given that,

standard deviation =  \sigma = 759.00

Margin of error = E = 19

At 80% confidence level the z is ,

Z\alpha/2 = Z0.1 = 1.282

sample size = n = [Z\alpha/2* \sigma / E] 2

n = ( 1.282* 759 / 19 )2

n =2622.722852

Sample size = n =2623

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