Question

A 1.00 liter solution contains 0.35M acetic acid and 0.26 M potassium acetate. If 35.0 mL of water are added to this system,A 1.00 liter solution contains 0.45 M hypochlorous acid and 0.59 M potassium hypochlorite. If 0.300 moles of sodium hydroxide

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Answer #1

Part A

Concentration of acetic acid

= [moles of acetic acid /volume of solution (L)]

So, if volume is increased therefore the concentration of CH3COOH decreases (true).

and concentration of acetate ion alse decreases , hence their ratio will be same.

pH = pKa + log[CH3COO-]/[CH3COOH]

Hence,

Other statements are false.

Part B

If 0.300 mole NaOH is added then it reacts with hypochlorous acid to give hypochlorite ion .

NaOH + HClO \to NaClO + H2O

Hence, the number of moles of HClO will decrease (true).

The number of moles of ClO- will increase (true) .

Equilibrium concentration of H3O+ remain the same (false) .

pH will decrease ( false).

The ratio of [HClO] /[ClO-] will decrease (false).

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