A parallel-plate capacitor has plates of area 2.88×10−4 m2 . Part A. What plate separation is...
A parallel-plate capacitor has plates of area 2.88×10−4 m2 .
Part A.
What plate separation is required if the capacitance is to be 1660 pF ? Assume that the space between the plates is filled with air? (Dielectric constant for air is 1.00059)
Express your answer using three significant figures.d= ? μm
Part B
What plate separation is required if the capacitance is to be 1660 pF ? Assume that the space between the plates is filled with paper. (Dielectric constant for paper is 3.7)
Express your answer using two significant figures. d= ? μm
Please show all of your steps, thank you!
Homework Answers
C = epsilon _not * A / d
a)
1660*10^-12 = 8.85*10^-12* 2.88*10^-4 / d
d = 1.535 um
========
b)
1660 *10^-12 = 3.7* 8.85*10^-12* 2.88*10^-4/ d
d = 5.7 um
=======
Comment in case any doubt, will reply for sure.. Goodluck
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